rust/derive-hrtb-for-bare-fn-field-with-lifetime.rs at 51b51b51d7931da85280382a81c4dd80c73ca754 - rust - Gitea: Git with a cup of tea

rust-lang/rust

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Esteban Küber e7ad2da7f1 When deriveing, account for HRTB on BareFn fields

When given

```rust
trait SomeTrait {
    type SomeType<'a>;
}

struct Foo<T: SomeTrait> {
    x: for<'a> fn(T::SomeType<'a>)
}
```

expand to

```rust
impl<T: ::core::clone::Clone + SomeTrait> ::core::clone::Clone for Foo<T>
    where for<'a> T::SomeType<'a>: ::core::clone::Clone {
    #[inline]
    fn clone(&self) -> Foo<T> {
        Foo { x: ::core::clone::Clone::clone(&self.x) }
    }
}
```

instead of the previous invalid

```
impl<T: ::core::clone::Clone + SomeTrait> ::core::clone::Clone for Foo<T>
    where T::SomeType<'a>: ::core::clone::Clone {
    #[inline]
    fn clone(&self) -> Foo<T> {
        Foo { x: ::core::clone::Clone::clone(&self.x) }
    }
}
```

Fix #122622.

2024-06-04 20:46:03 +00:00

14 lines

271 B

Rust

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 //@ run-pass
 // Issue #122622: `#[derive(Clone)]` should work for HRTB function type taking an associated type
 #![allow(dead_code)]
 trait SomeTrait {
     type SomeType<'a>;
 }
 #[derive(Clone)]
 struct Foo<T: SomeTrait> {
     x: for<'a> fn(T::SomeType<'a>)
 }
 fn main() {}