Change DST syntax: type -> Sized?
closes #13367 [breaking-change] Use `Sized?` to indicate a dynamically sized type parameter or trait (used to be `type`). E.g., ``` trait Tr for Sized? {} fn foo<Sized? X: Share>(x: X) {} ```
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@@ -491,8 +491,8 @@ pub fn fold_ty_param<T: Folder>(tp: &TyParam, fld: &mut T) -> TyParam {
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TyParam {
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ident: tp.ident,
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id: id,
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sized: tp.sized,
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bounds: tp.bounds.map(|x| fold_ty_param_bound(x, fld)),
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unbound: tp.unbound.as_ref().map(|x| fold_ty_param_bound(x, fld)),
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default: tp.default.map(|x| fld.fold_ty(x)),
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span: tp.span
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}
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@@ -666,7 +666,7 @@ pub fn noop_fold_item_underscore<T: Folder>(i: &Item_, folder: &mut T) -> Item_
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methods.iter().map(|x| folder.fold_method(*x)).collect()
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)
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}
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ItemTrait(ref generics, ref sized, ref traits, ref methods) => {
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ItemTrait(ref generics, ref unbound, ref traits, ref methods) => {
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let methods = methods.iter().map(|method| {
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match *method {
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Required(ref m) => Required(folder.fold_type_method(m)),
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@@ -674,7 +674,7 @@ pub fn noop_fold_item_underscore<T: Folder>(i: &Item_, folder: &mut T) -> Item_
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}
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}).collect();
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ItemTrait(fold_generics(generics, folder),
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*sized,
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unbound.clone(),
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traits.iter().map(|p| fold_trait_ref(p, folder)).collect(),
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methods)
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}
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