Document pitfall with impl PartialEq<B> for A
Fixes #66476 by turning the violating example into an explicit counterexample.
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committed by
Robert Bamler
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618b01f9fa
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5028fd8ab9
@@ -135,10 +135,15 @@ use self::Ordering::*;
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/// By changing `impl PartialEq for Book` to `impl PartialEq<BookFormat> for Book`,
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/// we allow `BookFormat`s to be compared with `Book`s.
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///
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/// You can also combine these implementations to let the `==` operator work with
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/// two different types:
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/// A comparison like the one above, which ignores some fields of the struct,
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/// can be dangerous. It can easily lead to an unintended violation of the
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/// requirements for a partial equivalence relation. For example, if we kept
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/// the above implementation of `PartialEq<Book>` for `BookFormat` and added an
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/// implementation of `PartialEq<Book>` for `Book` (either via a `#[derive]` or
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/// via the manual implementation from the first example) then the result would
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/// violate transitivity:
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///
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/// ```
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/// ```should_panic
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/// #[derive(PartialEq)]
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/// enum BookFormat {
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/// Paperback,
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@@ -146,6 +151,7 @@ use self::Ordering::*;
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/// Ebook,
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/// }
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///
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/// #[derive(PartialEq)]
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/// struct Book {
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/// isbn: i32,
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/// format: BookFormat,
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@@ -163,18 +169,16 @@ use self::Ordering::*;
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/// }
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/// }
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///
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/// impl PartialEq for Book {
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/// fn eq(&self, other: &Book) -> bool {
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/// self.isbn == other.isbn
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/// }
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/// }
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///
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/// let b1 = Book { isbn: 3, format: BookFormat::Paperback };
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/// let b2 = Book { isbn: 3, format: BookFormat::Ebook };
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/// fn main() {
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/// let b1 = Book { isbn: 1, format: BookFormat::Paperback };
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/// let b2 = Book { isbn: 2, format: BookFormat::Paperback };
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///
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/// assert!(b1 == BookFormat::Paperback);
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/// assert!(BookFormat::Ebook != b1);
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/// assert!(b1 == b2);
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/// assert!(BookFormat::Paperback == b2);
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///
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/// // The following should hold by transitivity but doesn't.
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/// assert!(b1 == b2); // <-- PANICS
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/// }
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/// ```
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///
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/// # Examples
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