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libsyntax: Remove pub impl from the language

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This commit is contained in:
Patrick Walton
2013-06-03 16:56:35 -07:00
parent 9873f67e94
commit 16086ecff7
6 changed files with 25 additions and 27 deletions
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9
src/libsyntax/parse/parser.rs
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@@ -76,7 +76,7 @@ use parse::obsolete::{ObsoleteMoveInit, ObsoleteBinaryMove, ObsoleteSwap};
use parse::obsolete::{ObsoleteSyntax, ObsoleteLowerCaseKindBounds};
use parse::obsolete::{ObsoleteUnsafeBlock, ObsoleteImplSyntax};
use parse::obsolete::{ObsoleteTraitBoundSeparator, ObsoleteMutOwnedPointer};
use parse::obsolete::{ObsoleteMutVector, ObsoleteTraitImplVisibility};
use parse::obsolete::{ObsoleteMutVector, ObsoleteImplVisibility};
use parse::obsolete::{ObsoleteRecordType, ObsoleteRecordPattern};
use parse::obsolete::{ObsoletePostFnTySigil};
use parse::obsolete::{ObsoleteBareFnType, ObsoleteNewtypeEnum};
@@ -3305,10 +3305,9 @@ impl Parser {
None
};
// Do not allow visibility to be specified in `impl...for...`. It is
// meaningless.
if opt_trait.is_some() && visibility != ast::inherited {
self.obsolete(*self.span, ObsoleteTraitImplVisibility);
// Do not allow visibility to be specified.
if visibility != ast::inherited {
self.obsolete(*self.span, ObsoleteImplVisibility);
}
let mut meths = ~[];