12 lines
314 B
Python
12 lines
314 B
Python
# solves a quadratic equation in the form ax^2 + bx + c = 0
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def solve_quadratic(a, b, c):
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inside = b**2 - (4 * a * c)
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if (inside < 0):
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return None
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elif (inside == 0):
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return [-4/(2 * a)]
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else:
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return [(-b + inside**0.5) / (2 * a), (-b - inside**0.5) / (2 * a)]
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print(solve_quadratic(1, 5, 6))
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