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jps/python/function_2

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2020-02-17 11:58:19 -06:00
def solve_quadratic(a, b, c):
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inside = b**2 - (4 * a * c)
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if (inside < 0):
return None
elif (inside == 0):
return [-4/(2 * a)]
else:
return [(-b + inside**0.5) / (2 * a), (-b - inside**0.5) / (2 * a)]
print(solve_quadratic(1, 5, 6))