* fix(strings): use frequency-based signature for anagrams Replaced the sorting-based signature implementation with a frequency-based approach using `collections.Counter`. This ensures that the signature represents both characters and their counts, preventing collisions and better grouping of true anagrams. Examples: - "test" → "e1s1t2" - "finaltest" → "a1e1f1i1l1n1s1t2" - "this is a test" → " 3a1e1h1i2s3t3" Also updated the anagram lookup to use the new frequency-based signatures, making results more accurate and avoiding false positives. * Refactor anagram function return type to list[str] * Update anagrams.py * Update anagrams.py * Update anagrams.py * Update anagrams.py * [pre-commit.ci] auto fixes from pre-commit.com hooks for more information, see https://pre-commit.ci --------- Co-authored-by: Maxim Smolskiy <mithridatus@mail.ru> Co-authored-by: pre-commit-ci[bot] <66853113+pre-commit-ci[bot]@users.noreply.github.com>
52 lines
1.3 KiB
Python
52 lines
1.3 KiB
Python
from __future__ import annotations
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import collections
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import pprint
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from pathlib import Path
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def signature(word: str) -> str:
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"""
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Return a word's frequency-based signature.
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>>> signature("test")
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'e1s1t2'
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>>> signature("this is a test")
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' 3a1e1h1i2s3t3'
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>>> signature("finaltest")
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'a1e1f1i1l1n1s1t2'
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"""
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frequencies = collections.Counter(word)
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return "".join(
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f"{char}{frequency}" for char, frequency in sorted(frequencies.items())
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)
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def anagram(my_word: str) -> list[str]:
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"""
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Return every anagram of the given word from the dictionary.
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>>> anagram('test')
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['sett', 'stet', 'test']
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>>> anagram('this is a test')
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[]
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>>> anagram('final')
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['final']
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"""
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return word_by_signature[signature(my_word)]
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data: str = Path(__file__).parent.joinpath("words.txt").read_text(encoding="utf-8")
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word_list = sorted({word.strip().lower() for word in data.splitlines()})
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word_by_signature = collections.defaultdict(list)
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for word in word_list:
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word_by_signature[signature(word)].append(word)
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if __name__ == "__main__":
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all_anagrams = {word: anagram(word) for word in word_list if len(anagram(word)) > 1}
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with open("anagrams.txt", "w") as file:
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file.write("all_anagrams = \n")
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file.write(pprint.pformat(all_anagrams))
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