* Adding the function isProthNumber(n : int) which returns true if n is a Proth number * [pre-commit.ci] auto fixes from pre-commit.com hooks for more information, see https://pre-commit.ci * Fixing the issues of the isprothnumber function * [pre-commit.ci] auto fixes from pre-commit.com hooks for more information, see https://pre-commit.ci * New fixes on isprothnumber() * [pre-commit.ci] auto fixes from pre-commit.com hooks for more information, see https://pre-commit.ci * Fixes on isprothnumber() * Fixes on isprothnumber * Fixes on isprothnumber() * Fixes on isprothnumber * Update proth_number.py * Update proth_number.py * Update proth_number.py * Update proth_number.py * Update proth_number.py * Update proth_number.py * Update proth_number.py * Update proth_number.py --------- Co-authored-by: Juanitoupipou <juan.dupierris@imt-atlantique.net> Co-authored-by: pre-commit-ci[bot] <66853113+pre-commit-ci[bot]@users.noreply.github.com> Co-authored-by: Maxim Smolskiy <mithridatus@mail.ru>
126 lines
3.2 KiB
Python
126 lines
3.2 KiB
Python
"""
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Calculate the nth Proth number
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Source:
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https://handwiki.org/wiki/Proth_number
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"""
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import math
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def proth(number: int) -> int:
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"""
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:param number: nth number to calculate in the sequence
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:return: the nth number in Proth number
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Note: indexing starts at 1 i.e. proth(1) gives the first Proth number of 3
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>>> proth(6)
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25
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>>> proth(0)
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Traceback (most recent call last):
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...
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ValueError: Input value of [number=0] must be > 0
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>>> proth(-1)
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Traceback (most recent call last):
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...
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ValueError: Input value of [number=-1] must be > 0
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>>> proth(6.0)
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Traceback (most recent call last):
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...
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TypeError: Input value of [number=6.0] must be an integer
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"""
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if not isinstance(number, int):
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msg = f"Input value of [number={number}] must be an integer"
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raise TypeError(msg)
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if number < 1:
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msg = f"Input value of [number={number}] must be > 0"
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raise ValueError(msg)
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elif number == 1:
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return 3
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elif number == 2:
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return 5
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else:
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"""
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+1 for binary starting at 0 i.e. 2^0, 2^1, etc.
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+1 to start the sequence at the 3rd Proth number
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Hence, we have a +2 in the below statement
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"""
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block_index = int(math.log(number // 3, 2)) + 2
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proth_list = [3, 5]
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proth_index = 2
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increment = 3
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for block in range(1, block_index):
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for _ in range(increment):
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proth_list.append(2 ** (block + 1) + proth_list[proth_index - 1])
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proth_index += 1
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increment *= 2
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return proth_list[number - 1]
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def is_proth_number(number: int) -> bool:
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"""
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:param number: positive integer number
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:return: true if number is a Proth number, false otherwise
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>>> is_proth_number(1)
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False
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>>> is_proth_number(2)
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False
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>>> is_proth_number(3)
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True
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>>> is_proth_number(4)
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False
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>>> is_proth_number(5)
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True
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>>> is_proth_number(34)
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False
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>>> is_proth_number(-1)
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Traceback (most recent call last):
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...
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ValueError: Input value of [number=-1] must be > 0
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>>> is_proth_number(6.0)
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Traceback (most recent call last):
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...
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TypeError: Input value of [number=6.0] must be an integer
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"""
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if not isinstance(number, int):
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message = f"Input value of [{number=}] must be an integer"
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raise TypeError(message)
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if number <= 0:
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message = f"Input value of [{number=}] must be > 0"
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raise ValueError(message)
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if number == 1:
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return False
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number -= 1
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n = 0
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while number % 2 == 0:
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n += 1
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number //= 2
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return number < 2**n
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if __name__ == "__main__":
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import doctest
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doctest.testmod()
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for number in range(11):
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value = 0
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try:
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value = proth(number)
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except ValueError:
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print(f"ValueError: there is no {number}th Proth number")
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continue
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print(f"The {number}th Proth number: {value}")
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for number in [1, 2, 3, 4, 5, 9, 13, 49, 57, 193, 241, 163, 201]:
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if is_proth_number(number):
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print(f"{number} is a Proth number")
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else:
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print(f"{number} is not a Proth number")
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