68 lines
2.0 KiB
Python
68 lines
2.0 KiB
Python
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import math
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def escape_velocity(mass: float, radius: float) -> float:
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"""
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Calculates the escape velocity needed to break free from a celestial body's
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gravitational field.
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The formula used is:
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v = sqrt(2 * G * M / R)
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where:
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v = escape velocity (m/s)
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G = gravitational constant (6.67430 * 10^-11 m^3 kg^-1 s^-2)
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M = mass of the celestial body (kg)
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R = radius from the center of mass (m)
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Source:
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https://en.wikipedia.org/wiki/Escape_velocity
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Args:
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mass (float): Mass of the celestial body in kilograms.
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radius (float): Radius from the center of mass in meters.
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Returns:
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float: Escape velocity in meters per second, rounded to 3 decimal places.
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Examples:
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>>> escape_velocity(mass=5.972e24, radius=6.371e6) # Earth
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11185.978
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>>> escape_velocity(mass=7.348e22, radius=1.737e6) # Moon
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2376.307
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>>> escape_velocity(mass=1.898e27, radius=6.9911e7) # Jupiter
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60199.545
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>>> escape_velocity(mass=0, radius=1.0)
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0.0
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>>> escape_velocity(mass=1.0, radius=0)
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Traceback (most recent call last):
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...
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ZeroDivisionError: Radius cannot be zero.
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"""
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gravitational_constant = 6.67430e-11 # m^3 kg^-1 s^-2
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if radius == 0:
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raise ZeroDivisionError("Radius cannot be zero.")
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velocity = math.sqrt(2 * gravitational_constant * mass / radius)
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return round(velocity, 3)
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if __name__ == "__main__":
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import doctest
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doctest.testmod()
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print("Calculate escape velocity of a celestial body...\n")
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try:
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mass = float(input("Enter mass of the celestial body (in kgs): ").strip())
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radius = float(input("Enter radius from the center of mass (in ms): ").strip())
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velocity = escape_velocity(mass=mass, radius=radius)
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print(f"Escape velocity is {velocity} m/s")
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except ValueError:
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print("Invalid input. Please enter valid numeric values.")
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except ZeroDivisionError as e:
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print(e)
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